Answer:
The sequence is:
10, 30, 50, 70, 90.....................
Step-by-step explanation:
We have,
First term (a) = 10
Common difference (d) = ?
Sum of first 5 terms ([tex]S_{5}[/tex]) = 250
or, [tex]\frac{n}{2} [{2a+(n-1)d}] = 250[/tex]
or, [tex]\frac{5}{2} [2*10 + 4d]=250[/tex]
or, [tex]\frac{5}{2} * 4[5+d]=250[/tex]
or, 10(5 + d) =250
or, 5 + d = 25
∴ d = 20
Now,
2nd term = a + d = 10 + 20 = 30
3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50
4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70
5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90
