contestada

A ray of light passes from air into cubic zirconia at an angle of 56.0° to the normal. The angle of
refraction is 22.00°.
What is the index of refraction of cubic zirconia?

Respuesta :

Answer:

η = 2.2

Explanation:

The index of refraction is given by the following formula:

[tex]\eta = \frac{Sin\ \theta_i}{Sin\ \theta r}[/tex]

where,

η = index of refraction of cubic zirconia = ?

[tex]\theta_i[/tex] = angle of incidence = 56°

[tex]\theta_r[/tex] = angle of refraction = 22°

Therefore,

[tex]\eta = \frac{Sin\ 56^o}{Sin\ 22^o}\\\\\eta = \frac{0.829}{0.375}[/tex]

η = 2.2