Answer:
[tex]\frac{dy}{dx}[/tex] = - [tex]\frac{3}{2x^{\frac{3}{2} } }[/tex]
Step-by-step explanation:
Differentiate using the power rule
[tex]\frac{d}{dx}[/tex] (a[tex]x^{n}[/tex] ) = na[tex]x^{n-1}[/tex]
Given
y = [tex]\frac{3}{\sqrt{x} }[/tex] = 3[tex]x^{-\frac{1}{2} }[/tex] , then
[tex]\frac{dy}{dx}[/tex] = - [tex]\frac{3}{2}[/tex] [tex]x^{-\frac{3}{2} }[/tex] = - [tex]\frac{3}{2x^{\frac{3}{2} } }[/tex]