Respuesta :
Answer:
203 grams
Explanation:
The no. of moles of (6.3 x 10²⁴ molecules--Avagadros number) of NH₃ = (1.0 mol)(7.2 x 10²⁴ molecules)/(6.022 x 10²³ molecules) = 11.96 mol.
The no. of grams of NH₃ present = no. of moles x molar mass = (11.96 mol)(17.0 g/mol) = 203.3 g ≅ 203.0 g.
The answer is the mass of a sample of NH3 containing 7.20 x 1024 molecules of NH3 is 203 grams.
What is a molecule ?
A molecule is a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance.
6.02214076 × 10²³ molecules constitutes 1 mole of NH₃
7.20 x 10²⁴ molecules constitutes of
[tex]\rm\dfrac{7.20 \times 10^{24}}{6.02\times 10^{23}}\\[/tex]
=11.19 moles
1 mole of NH₃ = 17 gm
11.19 mole will be = 17 * 11.19
= 203 grams
Therefore the mass of a sample of NH3 containing 7.20 x 1024 molecules of NH3 is 203 grams.
To know more about molecule
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