Respuesta :
The total number of games a girl play against a boy is 25, the number of games a girl plays against a boy is 10, the fraction of the games are boy-versus-boy is 2/9, and 1/5 fraction of all games at the tournament Anita plays the game.
We have given that,
Of the 10 kids in a chess club, 5 are left-handed and 5 are right-handed.
What are permutation and combination?
A permutation can be defined as the number of ways a set can be arranged, order matters but in combination, the order does not matter.
We have 5 girls and 5 boys in a chess club:
There are a total of 5×5 games girls play against a boy.
= 5×5
= 25
The number of games a girl play against another.
It is a combination problem so the total number of games:
= 10
A fraction of the games are boy-versus-boy:
The number games boy-versus-boy = 10
The number games Boy vs Boy & Girl vs Girl & Boy vs Girl
= 10+10+25
= 45
So the fraction = 10/45 ⇒ 2/9
If Anita is one of the club members then Anita will have to play against 9 people at the tournament.
Total number of games = 45
Then the fraction = 9/45 ⇒ 1/5
Thus, the total number of games a girl play against a boy is 25, the number of games a girl plays against a boy is 10, the fraction of the games are boy-versus-boy is 2/9, and 1/5 fraction of all games at the tournament Anita play the game.
To learn more about combination visit:
brainly.com/question/4546043
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