Complete Question
Analyze the boundary work done during the process having a rigid tank contains air at 500 kPa and 150°C. As a result of heat transfer to the surroundings, the temperature and pressure inside the tank drop to 65°C and 400 kPa, respectively.
Determine the boundary work done during this process and heat Lose
Answer:
a) Â [tex]W=0[/tex]
b) Â [tex]dQ=-61.03KJ/kg[/tex]
Explanation:
From the question we are told that:
Pressure of air [tex]P_1=500kpa[/tex]
Temperature of Air [tex]T_2=150°C[/tex]
Pressure drop [tex]P_2=400kpa[/tex]
Temperature of drop [tex]T_2=65 \textdegree C[/tex]
Generally the Constant Volume Process  is mathematically given by
 [tex]V_1=V_2=V[/tex]
Therefore
a)
Generally the equation for  boundary work w is mathematically given by
 [tex]W=pdv[/tex]
 [tex]W=P(V_2-V_1)[/tex]
 [tex]W=P(V_V)[/tex]
 [tex]W=0KJ[/tex]
b)
Generally the equation for Heat Change is mathematically given by
 [tex]dQ=dU+dW[/tex]
 [tex]dQ=dU[/tex]
 [tex]dQ=C_v(T_2-T_1)[/tex]
Where
  C_v=Specific Heat capacity of Air
 [tex]C_v=0.718 kJ/kg K[/tex]
 [tex]dQ=0.718(338-423)[/tex]
 [tex]dQ=-61.03KJ/kg[/tex]
