Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide [tex](H_{2}O_{2})[/tex].
Explanation:
Number of moles is defined as the mass of substance divided by its molar mass.
The molar mass of [tex]H_{2}O_{2}[/tex] is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.
[tex]Moles = \frac{mass}{molarmass}\\16.95 mol = \frac{mass}{34.01 g/mol}\\mass = 576.46 g[/tex]
Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide [tex](H_{2}O_{2})[/tex].
