Respuesta :
Answer: The molarity of iodide ions in given solution is 0.181 M.
Explanation:
Given: Mass = 1.97 g
Volume = 34.2 mL (1 mL = 0.001 L) = 0.0342 L
Molar mass of [tex]ZnI_{2}[/tex] = 319.22 g/mol
Moles is the mass of substance divided by its molar mass. Hence, moles of [tex]ZnI_{2}[/tex] are calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{1.97 g}{319.22 g/mol}\\= 0.0062 mol[/tex]
Molarity is the number of moles of a substance present in liter of a solution.
So, molarity of given solution is calculated as follows.
[tex]Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.0062 mol}{0.0342 L}\\= 0.181 M[/tex]
Thus, we can conclude that molarity of iodide ions in given solution is 0.181 M.
