Answer:
With replacement
[tex]probability \ of \ spade = \frac{13}{52} = \frac{1}{4} \\\\ probability \ of red\ card = \frac{26}{52} =\frac{1}{2}[/tex]
[tex]probability \ of \ spade \ then \ red\ card\ without\ replacement =[/tex][tex]\frac{1}{4} \times \frac{1}{2} = \frac{1}{8}[/tex]
Without replacement
[tex]probability \ of\ spade = \frac{13}{52} = \frac{1}{4} \\\\probability \ of \ spade\ again =\frac{12}{51} = \frac{4}{17}[/tex]
[tex]probability \ of \ spade \ then \ red\ card\ without\ replacement = \frac{1}{4} \times\frac{4}{17} =\frac{1}{17}[/tex]