Respuesta :

Answer:

2,325.6

Explanation:

You use the formula

Q =mco

M =mass =68

C=0.9

O=temperature increases =93-55=38

Then multiple all this 3

Q=68*0.9*38

The number of joules of heat that is needed to heat 68.00 grams of aluminum foil is 2,325.6.

What is specific heat?

The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.

By the formula of heat

Q = mct

The mass of aluminum is 68.00

the difference in temperature is 93.00 °C - 55.00 °C = 38.00

The specific heat is 0.90 J/g

Putting the values in the equation

[tex]Q = mct\\\\Q = 68.00 \times 0.90 \times 38.00 = 2325.6[/tex]

Thus, the joules of heat is 2325.6 J.

Learn more about specific heat

https://brainly.com/question/11297584

#SPJ2