Answer:
The correct solution is:
(a) 1680 W
(b) 504 W
(c) 1.240
Explanation:
The given values are:
Voltage,
V = 120 V
Current of blow dryer,
I₁ = 14 A
Current of vacuum cleaner,
I₂ = 4.2 A
Time,
t₁ = 16 min
t₂ = 43 min
As we know,
⇒ [tex]Power (P) = VI[/tex]
(a)
For blow dryer:
⇒ [tex]P_1=V\times I_1[/tex]
[tex]=120\times 14[/tex]
[tex]=1680 \ W[/tex]
(b)
For Vacuum cleaner:
⇒ [tex]P_2=V\times I_2[/tex]
[tex]=120\times 4.2[/tex]
[tex]=504 \ W[/tex]
(c)
The ratio will be:
= [tex]\frac{Blow \ dryer \ energy}{Vacuum \ cleaner \ energy}[/tex]
= [tex]\frac{P_1\times t_1}{P_1\times t_2}[/tex]
= [tex]\frac{1680\times 16}{504\times 43}[/tex]
= [tex]\frac{26880}{21672}[/tex]
= [tex]1.240[/tex]
