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A sheet of glass having an index of refraction of 1.52 is to be coated with a film of material having a refractiveindex of 1.75 such that green light with a wavelength of 525 nm (measured in vacuum) is preferentially transmitted when white light is incident normally on the film.What is the minimum thickness of the film that will achieve this result

Respuesta :

Cricetus

Answer:

The correct answer is "164.06 nm".

Explanation:

Refractive index,

n = 1.75

Wavelength,

λ = 525 nm

Now,

The maximum thickness of the film will be:

⇒ [tex]t=\frac{\lambda}{2n}[/tex]

On substituting the values, we get

⇒    [tex]=\frac{525}{2\times 1.75}[/tex]

⇒    [tex]=\frac{525}{3.5}[/tex]

⇒    [tex]=164.06 \ nm[/tex]