A cafe has a lunch menu with 4 sandwiches, 3 drinks, and 2 desserts. If you had to choose 1 sandwich, 1 drink, and 1 dessert, how many outcomes are possible?
A. 9
b. 24
c. 27
d. 33

Can someone pls answer my question ? I need an your answer and your explanation.

Respuesta :

Answer:

b. 24

Step-by-step explanation:

by multiplication rule ( probability theory) :

4×3×2 = 24

No of outcomes

  • Product of elements
  • 4(3)(2)(1)
  • 4!
  • 24

Option B