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Write the standard equation of the circle with center (5,-4) and radius 3.
OA (-5)2 + (y + 42 =9
B. (x + 5)2 + (y-4)2 = 9
C. (x+4)2 = (y-5)2 = 3
D. (x+5)2 + (-4)2 =3

Write the standard equation of the circle with center 54 and radius 3 OA 52 y 42 9 B x 52 y42 9 C x42 y52 3 D x52 42 3 class=

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aklee18oo

Answer:

A. (x - 5)^2 + (y + 4)^2 = 9

Step-by-step explanation:

The standard equation of a circle is in the form:

(x - h)^2 + (y - k)^2 = r^2

where (h, k) is the center and r is the radius. We can substitute what we have:

(x - 5)^2 + (y + 4)^2 = 9

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