Answer:
(47,16)
Step-by-step explanation:
System of Equations Problem.
Solve v(7)+b(6)=394;v(3)+b(12)=612
Solve 6b+7v=394 for b
Add -7v to both sides.
6b+7v+−7v=394+−7v
6b=−7v+394
Divide both sides by 6.
[tex]b=\frac{-7}{6} v+\frac{197}{3}[/tex]
Substitute [tex]b=\frac{-7}{6} v+\frac{197}{3}[/tex] for b in 12b+3v=612
12b+3v=612
[tex]12(\frac{-7}{6} v+\frac{197}{3} )+3v=612[/tex]
Simplify both sides of the equation.
−11v+788=612
Add -788 to both sides.
−11v+788+−788=612+−788
−11v=−176
[tex]\frac{-11v}{-11} =\frac{-176}{-11}[/tex]
v=16
Substitute 16 for v in [tex]b=\frac{-7}{6} v+\frac{197}{3}[/tex]
[tex]b=\frac{-7}{6} v+\frac{197}{3}[/tex]
[tex]b=\frac{-7}{6}(16)+\frac{197}{3}[/tex]
Simplify both sides of the equation.
b=47
Answer:
b=47 and v=16
