Answer:
Following are the solution to the given question.
Step-by-step explanation:
Please find the graph file and its solution in the attachment. Â
[tex]4x-15=3x+28\\\\4x-3x=28+15\\\\x=43\\\\[/tex]
Similarly:
[tex]3y+5=2y+50\\\\3y-2y=-5+50\\\\y=45\\\\[/tex]
For point 1:[tex]\to KR=4x-15= 4\times 43-15=172-15=157[/tex]
For point 2: [tex]\to BR=2y+50= 2\times 43+50=86+50=136[/tex]
For point 3:[tex]\to BE=KR=157[/tex]
For point 4:[tex]\to Kf=BR=130[/tex]
For point 5:[tex]\to ERK=KFB=180^{\circ} -\angle B-\angle ERB = 180^{\circ}-92^{\circ}-18^{\circ}=70^{\circ}[/tex]
Given that ΔKER and ΔBRE are congruent triangles, therefore:
1. How far KFC is from RCBC = KR = 157 m
2. How far BaliwagLetchon Manok is from RCBC Savings Bank = BR = 140 m
3. How far Baliwag Lechon is from his residence = BE = KR = 157 m
4. Â How far KFC is from his residence = KE = BR = 140 m
5. The measure of ∠ERK = 70°
Congruent triangles have corresponding parts hat are congruent to each other.
Thus, given that ΔKER ≅ ΔBRE, find the values of x and y as shown below:
KR = BE
4x - 15 = Â 3x + 28
4x - 3x = 15 + 28
x = 43
KE = BR
3y + 5 = 2y + 50
3y - 2y = -5 + 50
y = 45
Thus:
1. How far KFC is from RCBC = KR
KR = 4x - 15
Plug in the value of x
KR = 4(43) - 15
KR = 157 m
2. How far BaliwagLetchon Manok is from RCBC Savings Bank = BR
BR = 2y + 50
Plug in the value of y
BR = 2(45) + 50
BR = 140 m
3. How far Baliwag Lechon is from his residence = BE = KR = 157 m
4. Â How far KFC is from his residence = KE = BR = 140 m
5. The measure of ∠ERK = 180 - (92 + 18) = 70°
Learn more about congruent triangles on:
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