Answer:
t = 8.94 s
Explanation:
We will use the second equation of motion to calculate the time taken by the cart:
[tex]s = v_it + \frac{1}{2} at^2[/tex]
where,
s = distance = 200 m
vi = initial speed = 0 m/s
t = time taken = ?
a = acceleration = 5 m/s²
Therefore,
[tex]200\ m = (0\ m/s)(t)+\frac{1}{2}(5\ m/s^2)t^2\\\\t^2 = \frac{(200\ m)(2)}{5\ m/s^2}\\\\t = \sqrt{80\ s^s}[/tex]
t = 8.94 s
