Answer:
[tex] \large \boxed{ \boxed{ \tt x \geqslant 2 \: \: is \: \: the \: \: domain \: \: of \: \: function}}[/tex]
Step-by-step explanation:
We are given the square root function below:
[tex] \large{g(x) = \sqrt{x - 2} }[/tex]
Recall that domain is the set of all x-values and that a number inside the square root cannot be negative.
From the given square root function above, substituting x >= 2 gives a positive output. But if we substitute x < 2, evaluating the numbers inside result in negative number in the square root which does not exist in Real Number.
Hence,
[tex] \large{y = \sqrt{x - a} }[/tex]
And thus, the domain is
[tex] \large \boxed{x \geqslant a}[/tex]
Since if x < a, the output would become an imaginary number.
From the given function,
[tex] \large{g(x) = \sqrt{x - 2} }[/tex]
From the form of sqrt(x-a) where domain is a-term which is 2.
Since a = 2, and thus
[tex] \large \boxed{x \geqslant 2}[/tex]
