Answer:
solution below
Step-by-step explanation:
quadratic formula (note the + before the radical is ±)
[tex]\frac{-b+\sqrt{b^2-4*a*c}}{2a}}[/tex]
Let's plug in the numbers and simply for the first one
[tex]\frac{-(-8)+\sqrt{-8^2-4*2*5}}{2*2}}=\frac{8+\sqrt{24}}{4}}[/tex]
this simplies to
[tex]\frac{8+2\sqrt{6}}{4}=\frac{4+\sqrt{6}}{2}[/tex]
Do this same process with all the other ones
