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A bag of M&Ms contains 13 blue, 5 brown, 10 orange, 8 yellow, 8 red, and 4
green. Reaching into the bag, a person grabs 5 M&Ms.
What is the probability of getting no browns? Round to 3 decimal places.

Respuesta :

Answer:

0.5622 = 56.22% probability of getting no browns.

Step-by-step explanation:

The M&Ms are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this question:

13 + 5 + 10 + 8 + 8 + 4 = 48 total M&Ms, which means that [tex]N = 48[/tex]

Sample of 5 means that [tex]n = 5[/tex]

5 browns means that [tex]k = 5[/tex]

What is the probability of getting no browns?

This is P(X = 0).

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,48,5,5) = \frac{C_{5,0}*C_{43,5}}{C_{48,5}} = 0.5622[/tex]

0.5622 = 56.22% probability of getting no browns.