Answer:
Sipho catches up Jabu at 6:30 pm
Step-by-step explanation:
Jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h.
At 8:30 am, when Sipho leaves, we will have traveled 2.5 hours at 80 km/h, so he will be 80*2.5 = 200 km ahead.
From then, his position will be given by:
[tex]J(t) = 200 + 80t[/tex]
Sipho left town A to travel to town B. He drove at an average speed of 100 km/h.
His position will be given by:
[tex]S(t) = 100t[/tex]
At what time will Sipho catch up jabu?
He will catch up in t hours, and t is found when:
[tex]S(t) = J(t)[/tex]
So
[tex]100t = 200 + 80t[/tex]
[tex]20t = 200[/tex]
[tex]t = \frac{200}{20} = 10[/tex]
He will catch up 10 hours after 8:30 am, that is, 6:30 pm.
Sipho catches up Jabu at 6:30 pm
