The area of the composite figure = (8π + 12) [tex]inch^{2}[/tex].
The composite figure is made up of a semicircle and an isosceles triangle.
The area of a semicircle = (1/2)π[tex]r^{2}[/tex]
radius = 4 inch
When we substitute, the area of the semicircle is
= (1/2)π[tex]\times[/tex]16
= 8π [tex]$inch^{2}[/tex]
Area of the isosceles triangle = (1/2)bh
= (1/2)(4+4)[tex]\times[/tex]3
= 12 [tex]inch^{2}[/tex]
We add the two areas to acquire the area of the composite figure to be: (8π + 12) [tex]inch^{2}[/tex]
The area of the composite figure = (8π + 12) [tex]inch^{2}[/tex].
Therefore, the correct answer is option b. (8π + 12) in.2
To learn more about the area of semicircle
https://brainly.com/question/12920033
#SPJ2
