Graph the equation y = x2 + 8x + 12 on the accompanying set of axes. You must
plot 5 points including the roots and the vertex. Using the graph, determine the
vertex of the parabola.

Roots: set y = x^2 + 8x + 12 = 0 and solve for x: x + 6 = 0, so x = -6 is one root. The other is x = -2. The corresponding points are (-6, 0) and (-2, 0).

y-intercept: Let x = 0. Then y = 12. The y-intercept is (0, 12).

Axis of symmetry: x = -b / (2a) => x = -8/(2*1) = -4: x = -4

Vertex y-value: evaluate y at x = - 4: (-4)^2 + 8(-4) + 12 = -4: (-4, -4)

Arbitrarily chosen x value: x = 1 => 1^2 + 8(1) + 12 = 21: (1, 21)

The five points are: (-6, 0) and (-2, 0), (0, 12), (-4, -4), (1, 21). The vertex is (-4, -4). The parabolic graph opens UP.

Graph the equation y = x2 + 8x + 12 on the accompanying set of axes. You must plot 5 points including the roots and the vertex. Using the graph, determine the vertex of the parabola.

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Graph the equation y = x2 + 8x + 12 on the accompanying set of axes. You must
plot 5 points including the roots and the vertex. Using the graph, determine the
vertex of the parabola.