Respuesta :
The points On circle with a center at (0, 0) that includes the point (-1, -3) would be (0, 10).
What is the equation of the circle with radius r units, centered at (x,y) ?
If a circle O has a radius of r units length and that it has got its center positioned at (h, k) point of the coordinate plane,
then, its equation is given as:
[tex](x-h)^2 + (y-k)^2 = r^2[/tex]
We have given On circle with a center at (0, 0) that includes the point (-1, -3).
So the equation form
[tex](x-h)^2 + (y-k)^2 = r^2[/tex]
[tex](x-0)^2 + (y-0)^2 = r^2\\\\x^{2} +y^{2} =r^{2} \\\\(-1)^{2} +(-3)^{2} =r^{2} \\\\r^{2} = 10[/tex]
So, the other point that satisfies the equation would be (0, 10).
Learn more about the equation of a circle here:
https://brainly.com/question/10165274
#SPJ2
