Respuesta :

Answer:

Explanation:

1. Please provide the enthalpy info - I will work on it with the info

2.

i) Reaction a should be modified to match the number of S in equation:

 2S + 2O2 -> 2SO2     deltaH = -370kJ

ii) Reaction b should be written reversely to match the reactants of SO2:

 2SO2 + O2 -> 2SO3     deltaH = 256kJ

iii) Adding the equations together:

 2S + 3O2 -> 2SO3

iv) Enthalpy of the combined reaction = -370+256 = -114kJ

 It is negative so the reaction is exothermic.

Answer:

Explanation:

1 c. enthalpy change = enthalphies of formation of all products - enthalphies of formation of all reactants =  -526.3 kcal/mol

1 d. C3H8(g) + 5 O2 (g) → 3 CO2 (g)  + 4 H2O (l)    ΔH = -526.3 kcal/mol

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