Respuesta :
Answer:
The test statistic is t = 3.36.
Step-by-step explanation:
You're testing the claim that the mean difference is greater than 0.7.
At the null hypothesis, we test if the mean difference is of 0.7 or less, that is:
[tex]H_0: \mu \leq 0.7[/tex]
At the alternate hypothesis, we test if the mean difference is greater than 0.7, that is:
[tex]H_1: \mu > 0.7[/tex]
The test statistic is:
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.
0.7 is tested at the null hypothesis:
This means that [tex]\mu = 0.7[/tex]
A survey of 35 people was conducted to compare their self-reported height to their actual height.
This means that [tex]n = 35[/tex]
From the sample, the mean difference was 0.95, with a standard deviation of 0.44.
This means that [tex]X = 0.95, s = 0.44[/tex]
Calculate the test statistic
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{0.95 - 0.7}{\frac{0.44}{\sqrt{35}}}[/tex]
[tex]t = 3.36[/tex]
The test statistic is t = 3.36.
