What is the volume of a 12.2 g piece of metal with a density of 9.43 g/cm??

Answer:
1.29
Explanation:
You have to find the equation which is d=m/v. d is 9.43=12.2/v. You have to solve for v which you get 1.29
1.29 [tex]cm^3[/tex] is the volume of a 12.2 g piece of metal with a density of 9.43 g/cm.
Density is the measurement of how tightly a material is packed together.
Density =Mass ÷ volume
9.43=12.2 ÷ V
V = 1.29 [tex]cm^3[/tex]
Hence, 1.29 [tex]cm^3[/tex] is the volume of a 12.2 g piece of metal with a density of 9.43 g/cm.
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brainly.com/question/16894337
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