Answer: [tex]197.40\ m[/tex]
Explanation:
Given
final velocity at takeoff [tex]v=28.1\ m/s[/tex]
Acceleration of the plane can be [tex]a=2\ m/s^2[/tex]
Initial velocity is zero for the plane i.e. [tex]u=0[/tex]
Using the equation of motion
[tex]\Rightarrow v^2-u^2=2as\quad [\text{s=displacement}]\\\text{Insert the values}\\\Rightarrow (28.1)^2-0=2\times 2\times s\\\\\Rightarrow s=\dfrac{789.61}{4}\\\\\Rightarrow s=197.40\ m[/tex]
Thu,s the minimum length must be [tex]197.40\ m[/tex]
