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Two velocity vectors are added: one of magnitude 2.0 m/s and one of magnitude 4.0 m/s. Not knowing the respective directions, we can say that the magnitude of the sum of the vectors will be

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samuelonum1

Answer:

4.47

Explanation:

Given data

vector 1 = 2m/s

vector 2= 4 m/s

The expression for the magnitude of two vectors is

|a| = √v1^2+ v2^2

substitute

|a| = √2^2+ 4^2

|a| = √4+ 16

|a| = √20

|a| = 4.47

Hence the magnitude of the two vectors is 4.47

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