Answer:
2
Proof:
x^2 + 6x + 7 + 2 = x^2 + 6x + 9 = x^2 + 6x + 3^2 = (x + 3)^2
The value can you add in the blank in the expression [tex]x^2 + 6x + 7 +\textunderscore\textunderscore[/tex] to complete the square is 2
"It is a polynomial which consists of three terms."
"A square trinomial is a perfect square, if and only if it satisfies the condition b² = 4ac"
For given question,
We have been given a square trinomial.
[tex]x^2 + 6x + 7 +\textunderscore\textunderscore[/tex]
We need to find the number in the blank space, so that the given trinomial would be complete square.
Let 'm' be the required number.
So, the trinomial would be [tex]x^2 + 6x + (7 +m)[/tex]
Comparing above square trinomial with [tex]ax^{2} +bx+c[/tex],
we have a = 1, b = 6, c = 7 + m
We know, a square trinomial is a perfect square, if and only if it satisfies the condition b² = 4ac
⇒ b² = 4ac
⇒ 6² = 4 × 1 × (7 + m)
⇒ 36 = 4 × (7 + m)
⇒ 9 = 7 + m
⇒ m = 2
This means, we need to add 2 in the blank space.
So, the square trinomial would be,
[tex]x^2 + 6x + 7 + \underline {2}\\\\= x^2 + 6x + 9\\\\= (x + 3)^2[/tex]
Therefore, the value can you add in the blank in the expression [tex]x^2 + 6x + 7 +\textunderscore\textunderscore[/tex] to complete the square is 2
Learn more about perfect square trinomial here:
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