Answer: 2000.25 ft
Step-by-step explanation:
Given
Height of lighthouse [tex]h=175\ ft[/tex]
Angle of elevation [tex]\theta=5^{\circ}[/tex]
Suppose, you are x feet away from lighthouse
From the figure, we can write
[tex]\Rightarrow \tan 5^{\circ}=\dfrac{175}{x}\\\\\Rightarrow x=\dfrac{175}{\tan 5^{\circ}}\\\\\Rightarrow x=2000.26\ ft[/tex]
Thus, the ship is 2000.25 ft away from the light-house
