Answer:
The electric field is given by 4.5 N/C.
Explanation:
Charge density = 80 nC/m3
inner radius, r' = 1 mm
outer radius, r'' = 3 mm
distance, r = 4 mm
The linear charge density is given by
[tex]\lambda =\rho \times\pi\times (r''^2 - r'^2)\\\\\lambda = 80\times 10^{-9}\times 3.14\times 10^{-6}\times(9-1)\\\\\lambda = 2\times 10^{-12}\\[/tex]
The electric field is given by
[tex]E = \frac{\lambda }{4\pi\varepsilon_or}\\E=\frac{9\times 10^9\times 2 \times 10^{-12}}{0.004}\\\\E=4.5 N/C[/tex]
