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A hot air balloon is released and it rises at a speed of 15 mph. A

weather pattern introduces a wind headed west at 20 mph. The

hot air balloon is now redirected. What is the new direction of the

hot air balloon?

Respuesta :

Numenius

Answer:

The direction is 37 degree north of west.

Step-by-step explanation:

velocity of balloon, v = 15 mph upwards

velocity of wind, v' = 20 mph west wards

The direction is given by

[tex]tan\theta = \frac{15}{20}\\\\\theta = 37^o north of west[/tex]

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