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The system of equations can be solved using linear combination to eliminate one of the variables. 2x − y = −4 → 10x − 5y = −20 3x + 5y = 59 → 3x + 5y = 59 13x = 39 Which equation can replace 3x + 5y = 59 in the original system and still produce the same solution?

Respuesta :

MrRoyal

Answer:

[tex]13x=39[/tex]

Step-by-step explanation:

Given

[tex]2x - y = -4 \to 10x - 5y =-20[/tex]

[tex]3x +5y =59 \to 3x +5y = 59[/tex]

Required

What can replace [tex]3x +5y = 59[/tex] ?

We have:

[tex]10x - 5y =-20[/tex]

and

[tex]3x +5y = 59[/tex]

Add up both equations:

[tex]10x +3x-5y+5y=-20+59[/tex]

[tex]10x +3x=39[/tex]

[tex]13x=39[/tex]

Since [tex]13x=39[/tex] is a result of [tex]10x - 5y =-20[/tex] and [tex]3x +5y = 59[/tex],

[tex]13x=39[/tex] can replace [tex]10x +3x=39[/tex]

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