By substitution method,
[tex]y = 4x - 6[/tex]
[tex]3y = - 2x + 24[/tex]
[tex] \frac{3y - 24}{ - 2} = x[/tex]
[tex]y = 4( \frac{3y - 24}{ - 2} ) - 6[/tex]
[tex]y = \frac{12y}{ - 2} + \frac{ - 96}{ - 2} - 6[/tex]
[tex]y = \frac{12y}{ - 2} + 48 - 6[/tex]
[tex]y = \frac{12y}{ - 2} + 42[/tex]
[tex]y - 42 = \frac{12y}{ - 2} [/tex]
[tex] - 42 = \frac{12y}{ - 2} - y[/tex]
[tex] - 42 = \frac{12y}{ - 2} - \frac{ - 2y}{ - 2?} [/tex]
[tex] - 42 = \frac{12y + 2y}{ - 2} [/tex]
[tex] - 42 = \frac{14y}{ - 2} [/tex]
[tex] - 42 \times - 2 = 14y[/tex]
[tex]84 = 14y[/tex]
[tex] \frac{84}{14} = y[/tex]
[tex]6 = y[/tex]
[tex]\frac{3(6) - 24}{ - 2} = x[/tex]
[tex] \frac{18 - 24}{ - 2} = x[/tex]
[tex] \frac{ - 6}{ - 2} = x[/tex]
[tex]3 = x[/tex]
Therefore,
The solution is (3, 6).
