Answer:
option A
Step-by-step explanation:
The line splits the triangle ABC into two triangles with same base length.
Therefore ,
[tex]Area \ of \ ABC = Area \ of \ ABD + Area \ of \ CBD\\\\[/tex]
[tex]= (\frac{1}{2} \times base \times height) + (\frac{1}{2} \times base \times height)\\\\=(\frac{1}{2} \times AD \times BD) + (\frac{1}{2} \times CD \times BD)\\\\=(\frac{1}{2} \times AD \times BD) + (\frac{1}{2} \times AD \times BD)[/tex][tex][ \ Given : AD = \ CD \ ][/tex]
[tex]= 2 \times (\frac{1}{2} \times AD \times BD)\\\\= 2 \times Area \ of \ ABD[/tex]
