Given:
The given sets are:
[tex]U=\{x|x\in N\text{ and }x<10\}[/tex]
[tex]A=\{x|x\text{ is an odd natural number and }x<10\}[/tex]
[tex]B=\{x|x\text{ is an even natural number and }x<10\}[/tex]
[tex]C=\{x|x\in N\text{ and }3<x<5\}[/tex]
To find
The set [tex]B\cap U[/tex].
Solution:
We have,
[tex]U=\{x|x\in N\text{ and }x<10\}[/tex]
[tex]U=\{1,2,3,4,5,6,7,8,9\}[/tex]
[tex]B=\{x|x\text{ is an even natural number and }x<10\}[/tex]
[tex]B=\{2,4,6,8\}[/tex]
Now, [tex]B\cap U[/tex] is the set that contains all the common elements of both sets B and U.
[tex]B\cap U=\{2,4,6,8\}[/tex]
[tex]B\cap U=B[/tex]
Therefore, the correct option is A.
