The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y - 4 = 1/4(x - 8). What
iS the slope-intercept form of the equation for this line?
O y = 1/4x- 12
O y= 1/4x-4
O y= 1/4x+2
O y= 1/4x+6

Respuesta :

Answer:

3rd option

Step-by-step explanation:

The equation of a line in point slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

Given

y - 4 = [tex]\frac{1}{4}[/tex] (x - 8)

with m = [tex]\frac{1}{4}[/tex] and (a, b) = (8, 4 )

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept ) , then

y = [tex]\frac{1}{4}[/tex] x + c ← is the partial equation

To find c substitute (8, 4) into the partial equation

4 = 2 + c ⇒ c = 4 - 2 = 2

y = [tex]\frac{1}{4}[/tex] x + 2 ← equation in slope- intercept form