Answer:
[tex]C" = (-4,-3)[/tex]
Step-by-step explanation:
Given
[tex]C = (4,3)[/tex]
Required
The coordinates of C"
From the question, we understand that:
C is reflected over x-axis to give C'
The rule to this is:
[tex]C(x,y) \to C'(x,-y)[/tex]
So, we have:
[tex]C(4,3) \to C'(4,-3)[/tex]
Next, C' is reflected over y-axis to give C''
The rule to this is:
[tex]C'(x,y) \to C"(-x,y)[/tex]
So, we have:
[tex]C'(4,-3) \to C"(-4,-3)[/tex]