Answer:
[tex]x^2-10x+18=0[/tex]
a = -10 and b = 18.
Step-by-step explanation:
Let w represent the width of the rectangle.
We are given that the perimeter of the rectangle is 20 cm, this means that:
[tex]20=2(x + w)[/tex]
Let's put w in terms of x. Divide both sides by two:
[tex]10=x+w[/tex]
And solve for w:
[tex]w=10-x[/tex]
So, the rectangle measures x by (10 - x) cm.
According to the Pythagorean Theorem:
[tex]a^2+b^2=c^2[/tex]
a and b are the legs and c is the hypotenuse.
Substitute x for a, w for b, and 8 for c:
[tex]x^2+w^2=8^2[/tex]
Simplify and substitute:
[tex]x^2+(10-x)^2=64[/tex]
Square:
[tex]x^2+(100-20x+x^2)=64[/tex]
Isolate the equation. So:
[tex]2x^2-20x+36=0[/tex]
Since the leading coefficient is one, divide both sides by two:
[tex]x^2-10x+18=0[/tex]
Therefore, a = -10 and b = 18.
