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A javelin thrower is running at 7mph and throws her javelin at 18mph at an angle of 13o with the horizontal. Determine the resultant speed and direction of the javelin. i need the magnitude and the direction !!! HELP WILL MARK BRALIEST

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Will I get any points?
anvimalik867

Magnitude: 24.93 mph

Direction: 9.37°

A javelin thrower throws her javelin at an angle of 13o

cos13°=v1/18

v1=cos13° * 18= 17.54mph

v=v1+7

   17.54+7=24.54 mph

sin13°=v2/18

v2=sin13° * 18= 4.05mph

tan ∅ =v2/v=0.165

∅ =9.37°

cos ∅ =v/v3

v3=24.54/cos 9.37=24.93

What is the formula for resultant speed?

Multiply the acceleration by the time the object is being accelerated. For example, if an object falls for 3 seconds, multiply 3 by 9.8 meters per second squared, which is the acceleration from gravity. The resultant velocity in this case is 29.4 meters per second.

How do you find the resultant direction?

join the tail of the first vector with the second vector's head and put the arrowhead. To determine the magnitude, measure the length of the resultant R, and find out the direction.

Learn more about resultant force:https://brainly.com/question/14626208

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