Respuesta :
Answer:
0.7408 = 74.08% probability that there are no surface flaws in an auto's interior.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
In which
x is the number of successes
e = 2.71828 is the Euler number
[tex]\mu[/tex] is the mean in the given interval.
Mean of 0.03 flaws per square foot of plastic panel.
This means that [tex]\mu = 0.03n[/tex], in which n is the number of square feet.
Assume an automobile interior contains 10 square feet of plastic panel.
This means that [tex]n = 10[/tex], so [tex]\mu = 0.03(10) = 0.3[/tex]
What is the probability that there are no surface flaws in an auto's interior?
This is [tex]P(X = 0)[/tex]. So
[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]
[tex]P(X = x) = \frac{e^{-0.3}*(0.3)^{0}}{(0)!} = 0.7408[/tex]
0.7408 = 74.08% probability that there are no surface flaws in an auto's interior.
