An electric field is given by in units of N/C when is in meters. What is the potential difference from point B at (0,7) m to point A at (7,0) m

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Complete Question

An electric field is given by E= (5x, 0, 0) in units of N/C when x is in meters. What is the potential difference VA - VB from point B at (0,7) m to point A at (7,0) m? V

Answer:

[tex]V_A-V_B=-122.5V[/tex]

Explanation:

From the question we are told that:

Position of point [tex]B=(0,7) m[/tex]

Position of point [tex]A=(7,0) m[/tex]

Generally the equation for pd across the points is mathematically given by

 [tex]V_A-V_B=-\int_0^7(5x)d[/tex]

 [tex]V_A-V_B=-[\frac{5x^2}{2}]_0^7[/tex]

 [tex]V_A-V_B=-[\frac{5(7)^2}{2}][/tex]

 [tex]V_A-V_B=-122.5V[/tex]