Phosphorus trichloride can be made by the following reaction: P4(s) 6Cl2(g) - 4) 4PCl3(l) What is the maximum amount of phosphorus trichloride that can be formed if 15 molecules of P4 are mixed with 42 molecules of chlorine

Respuesta :

Answer:

48 molecules

Explanation:

From the given reaction:

[tex]\mathtt{P_4 + 6Cl_2\to 4PCl_3}[/tex]

i.e. 1 mole of Phosphorus react 6 moles of chlorine to yield 4 moles of PCl₃

This implies that for each Pâ‚„ molecule, we will require 6 molecules of Clâ‚‚

We are provided with 15 molecules of Pâ‚„ and 42 molecules of Clâ‚‚

Suppose we utilized the whole 15 molecules of Pâ‚„, we will require:

= 15 × 6 = 90 moles of Cl₂ which is not readily available except 42 are available.

If we utilized 42 molecules of Clâ‚‚, we will require 42/6 = 7 molecules of Pâ‚„ which is readily available.

From this analysis, we can opine that Clâ‚‚ serves as the limiting agent

∴

P₄ : Cl₂ : PCl₃ = 1 : 6 : 4 = 7 : 42 : 48

It implies that only 48 molecules of phosphorus trichloride will be formed.