Respuesta :

reinhard10158

Answer:

A.

Step-by-step explanation:

a strange question, as 2 answer options are actually possible, as they define valid domains for this function.

and if the range of the function would include imaginary numbers ("i"), all 4 would be correct.

the problem statement has to be much more precise. you can tell your teacher that.

but I assume, we base just on real numbers and want the biggest domain range. and that is A.

A. for x=1 we get sqrt(0) + 2, which is absolutely valid.

B. a square root of a negative number is undefined in the works of real numbers. we would need "i", the imaginary numbers, to make this a valid function.

C. is also valid. no bad values and expressions involved. it is just a snake range than A.

D. the same a for B.

MrRoyal

The domain of the function [tex]f(x) = \sqrt{x - 1} + 2[/tex] is [tex][1,\infty)[/tex]

How to determine the domain?

The function is given as:

[tex]f(x) = \sqrt{x - 1} + 2[/tex]

Set the radicand greater than or equal to 0

[tex]\sqrt{x - 1} \ge 0[/tex]

Take the square of both sides

[tex]x - 1 \ge 0[/tex]

Add 1 to both sides

[tex]x \ge 1[/tex]

This means the possible values of x starts from 1 till infinity

Hence, the domain of [tex]f(x) = \sqrt{x - 1} + 2[/tex] is [tex][1,\infty)[/tex]

Read more about domain at:

https://brainly.com/question/1770447

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