g The altitude of a triangle is increasing at a rate 2 inch/hour while the area of the triangle is decreasing at a rate of 0.5 square inch per hour. At what rate is the base of the triangle is changing when the altitude is 6 inch and the area is 24 square inch

Respuesta :

Answer:

The base of the triangle is decreasing at a rate of 1.4167 inch/hour.

Step-by-step explanation:

Area of a triangle:

The area of a triangle of base b and height h is given by:

[tex]A = bh[/tex]

In this question:

We have to derivate the equation of the area implicitly in function of time. So

[tex]\frac{dA}{dt} = b\frac{dh}{dt} + h\frac{db}{dt}[/tex]

The altitude of a triangle is increasing at a rate 2 inch/hour while the area of the triangle is decreasing at a rate of 0.5 square inch per hour.

This means that:

[tex]\frac{dh}{dt} = 2, \frac{dA}{dt} = -0.5[/tex]

At what rate is the base of the triangle is changing when the altitude is 6 inch and the area is 24 square inch?

This is [tex]\frac{db}{dt}[/tex] when [tex]h = 6[/tex]

Area is 24, so the base is:

[tex]A = bh[/tex]

[tex]24 = 6b[/tex]

[tex]b = \frac{24}{6} = 4[/tex]

Then

[tex]\frac{dA}{dt} = b\frac{dh}{dt} + h\frac{db}{dt}[/tex]

[tex]-0.5 = 4(2) + 6\frac{db}{dt}[/tex]

[tex]6\frac{db}{dt} = -8.5[/tex]

[tex]\frac{db}{dt} = -\frac{8.5}{6}[/tex]

[tex]\frac{db}{dt} = -1.4167[/tex]

The base of the triangle is decreasing at a rate of 1.4167 inch/hour.