5. A gas occupies a volume of 100.0 mL at 27.0°C and 630.0 torr. At what temperature, in degrees
Celsius, would a volume of 50.0 mL at 630.0 torr? (-123°C)

Respuesta :

100 by 500 ml so if you put 50 ml in 630torr it would evaporate

Explanation:

it is more than ¹00 celcwius so it would eveporate

Solution: The temperature, in degrees Celsius at volume of 50.0 mL and pressure 630.0 torr is -123°C.

It is given that a gas occupies,

[tex]V_{1}[/tex]= 100.0 mL, [tex]T_{1}[/tex]=27.0°C, [tex]P_{1}[/tex]=630.0 torr.

Also given as,  [tex]V_{2}[/tex]= 50.0 mL, [tex]P_{2}[/tex]=630.0 torr.

It is required to find the temperature, in degrees Celsius at volume of 50.0 mL and pressure 630.0 torr.

What is the temperature, in degrees

Celsius at volume of 50.0 mL and pressure 630.0 torr is -123?

As we know the relation between volume and temperature,

[tex]\frac{V_{1} }{T_{1} }[/tex][tex]=\frac{V_{2} }{T_{2} }[/tex]

[tex]{T_{2} } =\frac{{V_{2} .{T_{1} } }}{{V_{1} } }[/tex]

Putting the values, we have

[tex]{T_{2} } =\frac{50.300}{100} \\{T_{2} } =50.3\\{T_{2} } =150K[/tex]

This is the temperature in kelvin. So we have to convert it into degree Celsius.

[tex]T_{2}=150-273\\ T_{2}=-123°C[/tex]

Therefore, the temperature, in degrees Celsius at volume of 50.0 mL and pressure 630.0 torr is -123°C.

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