Step-by-step explanation:
Let H = HCF(A,B) and L = LCM(A,B)
Then A*B = L*H
Here L*H = 100*5 = 500
Also H <= A ,B <= L
So we need to find all A*B = 500, satisfying the above condition. This can be done using prime factorisation of 500.
Here 500 = 2^2 * 5^3
so possible values of A and B are
1 , 500
2, 250
4, 125
5,100
10,50
20,25
(assuming order doesn’t matter.)
so pairs satisfying given condition are → (20,25) and (100,5)
You can write a computer program in language of your choice to do it for other bigger numbers.
