Answer:
Since the lines are Perpendicular..
The Product of their Gradients = -1
m'm"=-1
m' from y=3x - 5 is 3
3.m" = -1
m" = -1/3.
Since Intercept on y axis = -2...
That of x at that point is =0
y-y' = m"(x-x")
y-(-2) = -1/3( x - 0)
y+2 = -1/3(x)
Multiplying through by 3
3y + 6 = -x
3y + x = -6. This is your Equation
To verify this.
Let's turn it into the Intercept form which is
x/a + y/b = 1
To get 1 at the right hand side... Divide through by -6
3y/-6 + x/-6 = 1
y/-2 - x/6 = 1
You could see directly below y is its intercept and thats -2
