Helppppppppp
What is the solution to the equation below ?

Answer: x=3
Step-by-step explanation:
First we're going to get rid of the fraction by multiplying both sides by the square root of x-2
Now square both sides
[tex](\sqrt{3x })^2=3^2(\sqrt{x-2 })^2\\3x=9(x-2)[/tex]
Next use the distributive property
[tex]3x=(9)(x)-(9)(2)\\3x=9x-18[/tex]
Now subtract 9x from both sides
[tex]3x-9x=9x-18-9x\\-6x=-18[/tex]
Finally divide -6 on both sides
[tex]\frac{-6x}{-6} =\frac{-18}{-6} \\x=3[/tex]